Our highlighted Algorithm for the week asks us to find the majority element in array that appears more than [n/2] times.
I have to admit, I had a hard time with this one. Luckily, I had the awesome support from my study group to help along the way.
I definitely learned a lot from it. Let’s get started!
Problem
Please click the link below to view the Problem Statement
Solution
For my own sanity, let’s breakdown what’s happening above. We declared a variable to hold the needed formula to find the majority element and an empty object in the newObj variable.
The
Math.floor()function returns the largest integer less than or equal to a given number. — MDN Docs
We created a for loop iterating through the nums array and declare the variable value to hold the index of nums. We’re then assigning a value to the newObj’s key and checking to see if the element exists. If it does, add 1 to the value, if not, make the value 1.
And finally, we make a conditional statement checking our newObj against the formula we declared on line 4.
As always, here is a faster, optimal, one liner solution! This is not my code! I’ve linked the programmer’s LeetCode solution below. Please check him out!
Conclusion
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Sources:
https://leetcode.com/problems/majority-element/discuss/1146085/javascript-one-liner ,
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Math/floor